In the circuit shown in the figure, every capacitor has a capacitance of 10 F . The battery provides an emf of 100 V . Determine the energy stored in each of the four capacitors.

Step-by-step solution

From the given circuit, capacitors b and c are connected in parallel, and their combination is in series with capacitors a and d . The equivalent capacitance of b and c is: C_ bc = C_b + C_c = 10 F + 10 F = 20 F The total equivalent capacitance of the circuit C_ eq is: 1 C_ eq = 1 C_a + 1 C_ bc + 1 C_d 1 C_ eq = 1 10 + 1 20 + 1 10 = 5 20 F ⁻¹ C_ eq = 4 F The total charge supplied by the battery is: Q = C_ eq V = 4 F 100 V = 400 C Since capacitors a and d are in series with the main circuit, the charge on each is: Q