In the given reaction sequence, the major product ' $C$ ' is :
${C}_{8}{H}_{10}\mathop{\overset{{HNO}_{3}}{⟶}}_{{H}_{2}{SO}_{4}}A\mathop{\overset{{Br}_{2}}{⟶}}_{\Delta}B\mathop{\overset{alcoholic}{⟶}}_{KOH}C$

Question

In the given reaction sequence, the major product ' C ' is : C _ 8 H _ 10 HNO _ 3 ⟶ _ H _ 2 SO _ 4 A Br _ 2 ⟶ _ Δ B alcoholic ⟶ _ KOH C

Quantrex Academy · Accepted Answer

Correct answer: B.

In the given reaction sequence, the major product ' C ' is : C _ 8 H _ 10 HNO _ 3 ⟶ _ H _ 2 SO _ 4 A Br _ 2 ⟶ _ Δ B

In first step nitration of benzene ring will take place at para position, since ethyl group is ortho-para directing in nature.

Then halogenation reaction will take place at benzyl position followed by dehydrohalogenation reaction with alcoholic KOH.

In the given reaction sequence, the major product ' C ' is : C _ 8...