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Concepts Of Physics MCQ Edition [Volume 2]
Exam
Concepts Of Physics MCQ Edition [Volume 2]
Subject
Physics
Chapter
Capacitors

Concepts Of Physics MCQ Edition [Volume 2] · Physics · Capacitors

A point charge Q is located at the origin. Determine the...

A point charge QQ is located at the origin. Determine the electrostatic energy stored outside a sphere of radius RR that is centred at the origin.

Options

  1. AQ28πε0R\dfrac{Q^2}{8\pi\varepsilon_0 R}
  2. BQ24πε0R\dfrac{Q^2}{4\pi\varepsilon_0 R}
  3. CQ216πε0R\dfrac{Q^2}{16\pi\varepsilon_0 R}
  4. DQ22πε0R\dfrac{Q^2}{2\pi\varepsilon_0 R}

Correct answer

A. Q28πε0R\dfrac{Q^2}{8\pi\varepsilon_0 R}

Step-by-step solution

The electric field at a distance rr from a point charge QQ is given by E=Q4πε0r2E = \dfrac{Q}{4\pi\varepsilon_0 r^2}.

The electrostatic energy density in the region is u=12ε0E2u = \dfrac{1}{2}\varepsilon_0 E^2.

The total electrostatic energy stored outside a sphere of radius RR is obtained by integrating the energy density over the volume from r=Rr = R to r=∞r = \infty.

U=∫R∞u dVU = \int_R^{\infty} u \, dV

Substituting uu and the volume element dV=4πr2drdV = 4\pi r^2 dr:

U=∫R∞12ε0(Q4πε0r2)24πr2drU = \int_R^{\infty} \dfrac{1}{2}\varepsilon_0 \left( \dfrac{Q}{4\pi\varepsilon_0 r^2} \right)^2 4\pi r^2 dr

U=∫R∞Q28πε0r2drU = \int_R^{\infty} \dfrac{Q^2}{8\pi\varepsilon_0 r^2} dr

U=Q28πε0[−1r]R∞U = \dfrac{Q^2}{8\pi\varepsilon_0} \left[ -\dfrac{1}{r} \right]_R^{\infty}

U=Q28πε0RU = \dfrac{Q^2}{8\pi\varepsilon_0 R}
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