A capacitor with a capacitance of 100 F is charged to a potential difference of 24 V . After disconnecting the charging battery, the capacitor is connected to a different battery of emf 12 V such that the positive plate of the capacitor is attached to the positive terminal of the battery. Determine the amount of charge that flows through the 12 V battery.

Step-by-step solution

Initial charge on the capacitor is q_i = C V_i q_i = 100 F 24 V = 2400 C When connected to the 12 V battery with matching polarities, the final potential difference across the capacitor becomes V_f = 12 V . Final charge on the capacitor is q_f = C V_f q_f = 100 F 12 V = 1200 C The amount of charge that flows through the battery is q = |q_f - q_i| q = |1200 C - 2400 C | = 1200 C