A capacitor of capacitance 5.00 F is charged to 24.0 V , while a second capacitor of capacitance 6.0 F is charged to 12.0 V . The positive plate of the first capacitor is subsequently connected to the negative plate of the second, and vice versa. During this process, there is a loss of electrostatic energy. What happens to this lost energy?

Step-by-step solution

When two charged capacitors are connected, charge redistributes between them until they reach a common potential. During this redistribution, a transient current flows through the connecting wires. Since the wires have some finite electrical resistance, a portion of the electrical energy is dissipated as heat due to Joule heating. Therefore, the lost electrostatic energy is dissipated as heat in the connecting wires.