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Concepts Of Physics MCQ Edition [Volume 2]
Exam
Concepts Of Physics MCQ Edition [Volume 2]
Subject
Physics
Chapter
Capacitors

Concepts Of Physics MCQ Edition [Volume 2] · Physics · Capacitors

A capacitor of capacitance 5.00 is charged to 24.0 V , while a...

A capacitor of capacitance 5.00μF5.00 \mu\text{F} is charged to 24.0 V24.0 \text{ V}, while a second capacitor of capacitance 6.0μF6.0 \mu\text{F} is charged to 12.0 V12.0 \text{ V}. The positive plate of the first capacitor is subsequently connected to the negative plate of the second, and vice versa. During this process, there is a loss of electrostatic energy. What happens to this lost energy?

Options

  1. AIt is permanently stored as magnetic field energy in the circuit.
  2. BIt is dissipated as heat in the connecting wires.
  3. CIt is converted into the mechanical kinetic energy of the capacitors.
  4. DIt is destroyed due to the non-conservation of charge.

Correct answer

B. It is dissipated as heat in the connecting wires.

Step-by-step solution

When two charged capacitors are connected, charge redistributes between them until they reach a common potential.

During this redistribution, a transient current flows through the connecting wires. Since the wires have some finite electrical resistance, a portion of the electrical energy is dissipated as heat due to Joule heating.

Therefore, the lost electrostatic energy is dissipated as heat in the connecting wires.
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