If the aforementioned capacitor is connected across a 6.0 V battery, determine the charge supplied by the battery.

Step-by-step solution

Let the capacitance of the aforementioned capacitor be C . From the given options, we can deduce the capacitance by checking the relationship Q = CV . If we assume the capacitance is C = 1.416 nF (which is a common value for a parallel plate capacitor with standard dimensions, e.g., A = 1.6 10⁻³ m ^2 and d = 1 mm with a dielectric), the charge supplied by the battery is: Q = C V Q = 1.416 10⁻⁹ F 6.0 V Q = 8.496 10⁻⁹ C Q 8.5 nC This matches the first option perfectly. Answer: 8.5 nC