If the aforementioned capacitor is connected across a 6.0 V battery, determine the net charge appearing on one of the coated surfaces.

Step-by-step solution

The capacitance of the parallel-plate capacitor formed by the coated surfaces is given by: C = K ₀ A d Using the standard parameters associated with this problem context (area A = 100 cm ^2 , thickness d = 1 mm , and dielectric constant K = 8 ): C = 8 8.854 10⁻¹² 100 10⁻⁴ 10⁻³ C = 7.083 10⁻¹⁰ F When the capacitor is connected across a 6.0 V battery, the net charge appearing on one of the coated surfaces is: Q = CV Q = (7.083 10⁻¹⁰) 6.0 Q = 4.2498 10⁻⁹ C Q 4.2 nC Answer: 4.2 nC