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Concepts Of Physics MCQ Edition [Volume 2]PhysicsCapacitors

A parallel-plate capacitor with a capacitance of 5 F is connected to a battery having an emf of 6 V . The separation between the plates is 2 mm . Determine the charge on the positive plate.

Options

  1. A60 C
  2. B30 C
  3. C15 C
  4. D1.2 C

Correct answer

B. 30 C

Step-by-step solution

The charge on a capacitor is given by the relation Q = CV . Given: Capacitance, C = 5 F Potential difference, V = 6 V Substituting the values: Q = 5 F 6 V = 30 C The separation between the plates ( d = 2 mm ) is not required for this calculation. The charge on the positive plate is 30 C .

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