In the following sequence of reactions, C _ 3 H _ 6 H ^ + / H _ 2 O ⟶ A(KIO)/(dilKOH)B + C . The compounds B and C respectively are :

Correct answer: D. CHI _ 3 , CH _ 3 COOK CH _ 3 CH = CH _ 2 H ^ + / H _ 2 O ⟶ CH _ 3 CHOHCH _ 3 (KIO)/(dilKOH) CHI _ 3 + CH _ 3 COOK

JEE Main 20211 SeptemberEvening Shift

Exam: JEE Main
Year: 2021
Date: 1 September
Shift: Evening Shift
Subject: Chemistry
Chapter: Hydrocarbons

JEE Main 2021 · 1 September · Evening Shift · Chemistry · Hydrocarbons

In the following sequence of reactions, C _ 3 H _ 6 H ^ + / H _ 2 O...

In the following sequence of reactions, ${C}_{3}{H}_{6}\overset{{H}^{+} / {H}_{2}O}{⟶}A\dfrac{KIO}{dilKOH}B + C$ . The compounds $B$ and $C$ respectively are :

Options

A ${CI}_{3}COOK, {CH}_{3}I$
B ${CH}_{3}I, HCOOK$
C ${CI}_{3}COOK, HCOOH$
D ${CHI}_{3}, {CH}_{3}COOK$

Correct answer

D. ${CHI}_{3}, {CH}_{3}COOK$

Step-by-step solution

${CH}_{3}CH = {CH}_{2}\overset{{H}^{+} / {H}_{2}O}{⟶}{CH}_{3}{CHOHCH}_{3}\dfrac{KIO}{dilKOH}{CHI}_{3} + {CH}_{3}COOK$

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