A capacitor with a capacitance of 100 is charged to a potential...

The capacitance of the capacitor is given as $C = 100 \mu\text{F} = 100 \times 10^{-6} \text{ F}$.

The potential difference across the capacitor is $V = 50 \text{ V}$.

The magnitude of the charge on each plate of the capacitor is given by the formula:

$Q = CV$

Substituting the given values:

$Q = (100 \times 10^{-6} \text{ F}) \times (50 \text{ V})$

$Q = 5000 \times 10^{-6} \text{ C}$

$Q = 5 \times 10^{-3} \text{ C}$

$Q = 5 \text{ mC}$