A capacitor with a capacitance of 100 F is charged to a potential difference of 50 V . Determine the magnitude of the charge on each plate.

Step-by-step solution

The capacitance of the capacitor is given as C = 100 F = 100 10⁻⁶ F . The potential difference across the capacitor is V = 50 V . The magnitude of the charge on each plate of the capacitor is given by the formula: Q = CV Substituting the given values: Q = (100 10⁻⁶ F ) (50 V ) Q = 5000 10⁻⁶ C Q = 5 10⁻³ C Q = 5 mC