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Concepts Of Physics MCQ Edition [Volume 2]
Exam
Concepts Of Physics MCQ Edition [Volume 2]
Subject
Physics
Chapter
Electric Current in Conductors

Concepts Of Physics MCQ Edition [Volume 2] · Physics · Electric Current in Conductors

At t = 0 , the plates of a capacitor of capacitance 10 ext ,...

At t=0t = 0, the plates of a capacitor of capacitance 10extμF10 ext{ }\mu\text{F}, charged to 60extμC60 ext{ }\mu\text{C}, are connected together by a wire having a resistance of 10extΩ10 ext{ }\Omega. Determine the charge on the capacitor in the circuit at t=30extμst = 30 ext{ }\mu\text{s}.

Options

  1. A32extμC32 ext{ }\mu\text{C}
  2. B44extμC44 ext{ }\mu\text{C}
  3. C22extμC22 ext{ }\mu\text{C}
  4. D18extμC18 ext{ }\mu\text{C}

Correct answer

B. 44extμC44 ext{ }\mu\text{C}

Step-by-step solution

The time constant of the discharging RC circuit is given by τ=RC\tau = RC.

Substituting the given values:
τ=10×10×10−6 s=100μs\tau = 10 \times 10 \times 10^{-6} \text{ s} = 100 \mu\text{s}

The charge on the capacitor during discharging is given by:
q=q0e−t/τq = q_0 e^{-t/\tau}

Substituting q0=60μCq_0 = 60 \mu\text{C} and t=30μst = 30 \mu\text{s}:
q=60e−30/100=60e−0.3μCq = 60 e^{-30/100} = 60 e^{-0.3} \mu\text{C}

Using the approximation e−0.3≈0.74e^{-0.3} \approx 0.74:
q≈60×0.74μC=44.4μCq \approx 60 \times 0.74 \mu\text{C} = 44.4 \mu\text{C}

The closest value among the given options is 44μC44 \mu\text{C}.
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