A triode possesses a mutual conductance of 2.0 millimho and a plate resistance of 20 k . To amplify a signal by a factor of 30 , what load resistance must be incorporated into the circuit?

Step-by-step solution

Given g_m = 2.0 millimho = 2 10⁻³ mho and r_p = 20 k = 20 10^3 . The amplification factor is given by: = r_p g_m = (20 10^3) (2 10⁻³) = 40 The voltage gain A_v of the amplifier is given by: A_v = R_L r_p + R_L Substituting the given values: 30 = 40 R_L 20 + R_L 600 + 30 R_L = 40 R_L 10 R_L = 600 R_L = 60 k