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Concepts Of Physics MCQ Edition [Volume 2]
Exam
Concepts Of Physics MCQ Edition [Volume 2]
Subject
Physics
Chapter
Heat and Temperature

Concepts Of Physics MCQ Edition [Volume 2] · Physics · Heat and Temperature

A constant volume thermometer indicates a pressure of 1.500 × 10^ 4...

A constant volume thermometer indicates a pressure of 1.500×104 Pa1.500 \times 10^{4} \text{ Pa} at the triple point of water, while at the normal boiling point it indicates 2.050×104 Pa2.050 \times 10^{4} \text{ Pa}. Determine the temperature at the normal boiling point.

Options

  1. A199.9 K199.9 \text{ K}
  2. B373.3 K373.3 \text{ K}
  3. C383.1 K383.1 \text{ K}
  4. D373.15 K373.15 \text{ K}

Correct answer

B. 373.3 K373.3 \text{ K}

Step-by-step solution

For a constant volume gas thermometer, the temperature TT is given by the relation:

T=Ttr×PPtrT = T_{tr} \times \dfrac{P}{P_{tr}}

where Ttr=273.16 KT_{tr} = 273.16 \text{ K} is the temperature at the triple point of water.

Given:
Ptr=1.500×104 PaP_{tr} = 1.500 \times 10^4 \text{ Pa}
P=2.050×104 PaP = 2.050 \times 10^4 \text{ Pa}

Substituting the values:

T=273.16×2.050×1041.500×104T = 273.16 \times \dfrac{2.050 \times 10^4}{1.500 \times 10^4}

T=273.16×205150T = 273.16 \times \dfrac{205}{150}

T=273.16×4130T = 273.16 \times \dfrac{41}{30}

T=373.318 KT = 373.318 \text{ K}

Rounding off to one decimal place, we get 373.3 K373.3 \text{ K}.
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