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Concepts Of Physics MCQ Edition [Volume 2]
Exam
Concepts Of Physics MCQ Edition [Volume 2]
Subject
Physics
Chapter
Heat and Temperature

Concepts Of Physics MCQ Edition [Volume 2] · Physics · Heat and Temperature

A steel rod is clamped rigidly at both ends. At 20^ ^ ^ C , the rod...

A steel rod is clamped rigidly at both ends. At 20^{}^{{}^{\circ}} C, the rod experiences zero tension. If the temperature increases to 100^{}^{{}^{\circ}} C, determine the force exerted by the rod on one of the clamps. The cross-sectional area of the rod is 2.00 mm22.00 \text{ mm}^2. The coefficient of linear expansion of steel is 12.0 \times 10^{-6} ^{}^{{}^{\circ}} C^{-1} and the Young's modulus of steel is 2.00×1011 N m−22.00 \times 10^{11} \text{ N m}^{-2}.

Options

  1. A480 N480 \text{ N}
  2. B192 N192 \text{ N}
  3. C384 N384 \text{ N}
  4. D96 N96 \text{ N}

Correct answer

C. 384 N384 \text{ N}

Step-by-step solution

The thermal stress developed in a rigidly clamped rod due to a change in temperature is given by σ=YαΔT\sigma = Y \alpha \Delta T.

The force exerted by the rod on the clamps is F=σA=YAαΔTF = \sigma A = Y A \alpha \Delta T.

Substituting the given values Y=2.00×1011 N m−2Y = 2.00 \times 10^{11} \text{ N m}^{-2}, A=2.00×10−6 m2A = 2.00 \times 10^{-6} \text{ m}^2, \alpha = 12.0 \times 10^{-6} ^{{}^{{}^{\circ}}}\textC^{-1}, and ΔT=100∘C−20∘C=80∘C\Delta T = 100^{{}^{{}^{\circ}}}\text{C} - 20^{{}^{{}^{\circ}}}\text{C} = 80^{{}^{{}^{\circ}}}\text{C}:

F=(2.00×1011)×(2.00×10−6)×(12.0×10−6)×80F = (2.00 \times 10^{11}) \times (2.00 \times 10^{-6}) \times (12.0 \times 10^{-6}) \times 80

F=4×12×80×10−1F = 4 \times 12 \times 80 \times 10^{-1}

F=384 NF = 384 \text{ N}
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