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Concepts Of Physics MCQ Edition [Volume 2]
Exam
Concepts Of Physics MCQ Edition [Volume 2]
Subject
Physics
Chapter
Heat Transfer

Concepts Of Physics MCQ Edition [Volume 2] · Physics · Heat Transfer

The left end of a copper rod (length = 20 cm , area of cross...

The left end of a copper rod (length =20 cm= 20 \text{ cm}, area of cross section =0.20 cm2= 0.20 \text{ cm}^2) is kept at 20^{}^{{}^{\circ}} \text{C} while the right end is kept at 80^{}^{{}^{\circ}} \text{C}. Ignoring any heat loss due to radiation, determine the temperature at a point 11 cm11 \text{ cm} from the left end. Thermal conductivity of copper = 385 \text{ W m}^{-1} ^{}^{{}^{\circ}} \textC^{-1}.

Options

  1. A33^{}^{{}^{\circ}} \text{C}
  2. B64^{}^{{}^{\circ}} \text{C}
  3. C47^{}^{{}^{\circ}} \text{C}
  4. D53^{}^{{}^{\circ}} \text{C}

Correct answer

D. 53^{}^{{}^{\circ}} \text{C}

Step-by-step solution

In steady state, the temperature gradient along a uniform rod is constant.

The temperature TT at a distance xx from the left end is given by

T=TL+TR−TLLxT = T_L + \dfrac{T_R - T_L}{L} x

Substituting the given values T_L = 20^{}^{{}^{\circ}} \text{C}, T_R = 80^{}^{{}^{\circ}} \text{C}, L=20 cmL = 20 \text{ cm}, and x=11 cmx = 11 \text{ cm}

T=20+80−2020×11T = 20 + \dfrac{80 - 20}{20} \times 11

T=20+6020×11T = 20 + \dfrac{60}{20} \times 11

T=20+3×11T = 20 + 3 \times 11

T = 20 + 33 = 53^{}^{{}^{\circ}} \text{C}
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