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Concepts Of Physics MCQ Edition [Volume 2]
Exam
Concepts Of Physics MCQ Edition [Volume 2]
Subject
Physics
Chapter
Heat Transfer

Concepts Of Physics MCQ Edition [Volume 2] · Physics · Heat Transfer

A copper rod is joined to a steel rod as shown in the figure. Both...

A copper rod is joined to a steel rod as shown in the figure. Both rods possess equal length and identical cross sectional area. The copper rod's free end is maintained at 0^{}^{{}^{\circ}} C while the steel rod's free end is maintained at 100^{}^{{}^{\circ}} C. Determine the temperature at the junction of the two rods. The thermal conductivity of copper is 390 \text{ W m}^{-1} ^{}^{{}^{\circ}} C^{-1} and that of steel is 46 \text{ W m}^{-1} ^{}^{{}^{\circ}} C^{-1}.
A copper rod is joined to a steel rod as shown in the figure. Both rods possess equal length and identical cross

Options

  1. A50.0^{}^{{}^{\circ}} C
  2. B10.6^{}^{{}^{\circ}} C
  3. C89.4^{}^{{}^{\circ}} C
  4. D11.8^{}^{{}^{\circ}} C

Correct answer

B. 10.6^{}^{{}^{\circ}} C

Step-by-step solution

Let the temperature at the junction be TT.

In steady state, the rate of heat flow through the copper rod is equal to the rate of heat flow through the steel rod.

KCuA(T−0)L=KSteelA(100−T)L\dfrac{K_{Cu} A (T - 0)}{L} = \dfrac{K_{Steel} A (100 - T)}{L}

Given that K_{Cu} = 390 \text{ W m}^{-1} ^{}^{{}^{\circ}} C^{-1} and K_{Steel} = 46 \text{ W m}^{-1} ^{}^{{}^{\circ}} C^{-1}, and the rods have equal length LL and identical cross-sectional area AA:

390(T−0)=46(100−T)390 (T - 0) = 46 (100 - T)

390T=4600−46T390 T = 4600 - 46 T

436T=4600436 T = 4600

T = \dfrac{4600}{436} \approx 10.55^{}^{{}^{\circ}} C

Rounding to one decimal place, we get T = 10.6^{}^{{}^{\circ}} C.
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