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Concepts Of Physics MCQ Edition [Volume 2]
Exam
Concepts Of Physics MCQ Edition [Volume 2]
Subject
Physics
Chapter
Heat Transfer

Concepts Of Physics MCQ Edition [Volume 2] · Physics · Heat Transfer

A room features a window equipped with a single 1.0 m × 2.0 m glass...

A room features a window equipped with a single 1.0 m×2.0 m1.0 \text{ m} \times 2.0 \text{ m} glass of thickness 2 mm2 \text{ mm}. Determine the rate of heat flow through the closed window if the temperature inside the room is 32^{}^{{}^{\circ}} C while the outside temperature is 40^{}^{{}^{\circ}} C. The thermal conductivity of the window glass is 1.0 \text{ J s}^{-1} \text{ m}^{-1} ^{}^{{}^{\circ}} C^{-1}.

Options

  1. A8000 J s−18000 \text{ J s}^{-1}
  2. B4000 J s−14000 \text{ J s}^{-1}
  3. C16000 J s−116000 \text{ J s}^{-1}
  4. D80 J s−180 \text{ J s}^{-1}

Correct answer

A. 8000 J s−18000 \text{ J s}^{-1}

Step-by-step solution

The rate of heat flow through a material is given by Fourier's law of heat conduction:

H=KAΔTdH = \dfrac{K A \Delta T}{d}

Given:
Area of the glass, A=1.0 m×2.0 m=2.0 m2A = 1.0 \text{ m} \times 2.0 \text{ m} = 2.0 \text{ m}^2
Thickness of the glass, d=2 mm=2×10−3 md = 2 \text{ mm} = 2 \times 10^{-3} \text{ m}
Temperature difference, \Delta T = 40^{}^{{}^{\circ}}\text{C} - 32^{}^{{}^{\circ}}\text{C} = 8^{}^{{}^{\circ}}\text{C}
Thermal conductivity, K = 1.0 \text{ J s}^{-1} \text{ m}^{-1} ^{}^{{}^{\circ}}\textC^{-1}

Substituting the values into the formula:

H=1.0×2.0×82×10−3H = \dfrac{1.0 \times 2.0 \times 8}{2 \times 10^{-3}}

H=162×10−3H = \dfrac{16}{2 \times 10^{-3}}

H=8000 J s−1H = 8000 \text{ J s}^{-1}
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