Consider the situation depicted in the figure. The frame is...

The thermal circuit consists of a parallel combination of the straight middle part and the bent part, connected in series with the two end parts.

The length of the straight middle part is $L_1 = 60 \text{ cm}$.

The length of the bent part is $L_2 = 5 \text{ cm} + 60 \text{ cm} + 5 \text{ cm} = 70 \text{ cm}$.

Since the frame is made of the same material and has a uniform cross-sectional area, the thermal resistance $R$ of any part is proportional to its length $L$ ($R = \dfrac{L}{KA}$).

Let the thermal resistance of the straight part be $R_1 = 60k$ and that of the bent part be $R_2 = 70k$, where $k$ is a constant.

The total heat current flowing through the system is given as $I = 130 \text{ J/s}$.

In a parallel combination, the heat current divides inversely as the thermal resistance. The heat current $I_2$ flowing through the bent part is:

$I_2 = I \times \dfrac{R_1}{R_1 + R_2}$

Substituting the values:

$I_2 = 130 \times \dfrac{60k}{60k + 70k}$

$I_2 = 130 \times \dfrac{60}{130}$

$I_2 = 60 \text{ J/s}$