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Concepts Of Physics MCQ Edition [Volume 2]
Exam
Concepts Of Physics MCQ Edition [Volume 2]
Subject
Physics
Chapter
Heat Transfer

Concepts Of Physics MCQ Edition [Volume 2] · Physics · Heat Transfer

Suppose that the total surface area of a human body is 1.6 m^2 and...

Suppose that the total surface area of a human body is 1.6 m21.6 \text{ m}^2 and it emits radiation like an ideal radiator. Determine the amount of energy radiated per second by the body if the body temperature is 37^{}^{{}^{\circ}} \text{C}. The Stefan constant σ\sigma is taken as 6.0×10−8 W m−2 K−46.0 \times 10^{-8} \text{ W m}^{-2} \text{ K}^{-4}.

Options

  1. A887 J/s887 \text{ J/s}
  2. B1419 J/s1419 \text{ J/s}
  3. C554 J/s554 \text{ J/s}
  4. D443 J/s443 \text{ J/s}

Correct answer

A. 887 J/s887 \text{ J/s}

Step-by-step solution

Given, surface area A=1.6 m2A = 1.6 \text{ m}^2

Temperature T = 37^{}^{{}^{\circ}} \text{C} = 37 + 273 = 310 \text{ K}

Stefan constant σ=6.0×10−8 W m−2 K−4\sigma = 6.0 \times 10^{-8} \text{ W m}^{-2} \text{ K}^{-4}

Since the body acts as an ideal radiator, emissivity e=1e = 1.

The amount of energy radiated per second is given by the Stefan-Boltzmann law:

P=σeAT4P = \sigma e A T^4

Substituting the given values:

P=(6.0×10−8)×1×1.6×(310)4P = (6.0 \times 10^{-8}) \times 1 \times 1.6 \times (310)^4

P=9.6×10−8×9235210000P = 9.6 \times 10^{-8} \times 9235210000

P=9.6×92.3521P = 9.6 \times 92.3521

P=886.58 J/sP = 886.58 \text{ J/s}

Rounding to the nearest integer, we get 887 J/s887 \text{ J/s}.
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