Concepts Of Physics MCQ Edition [Volume 2]PhysicsHeat Transfer
A metal block having a heat capacity of 80 J ^ C ⁻¹ is located in a room at 20^ C and is heated electrically. Once the temperature attains 30^ C , the heater is turned off. Just after the heater is turned on, the block's temperature increases at a rate of 2^ C s ⁻¹ , and just after it is turned off, the temperature decreases at a rate of 0.2^ C s ⁻¹ . Assuming Newton's law of cooling is valid, determine the power rad
Options
- A8 W
- B4 W
- C16 W
- D12 W
Correct answer
A. 8 W
Step-by-step solution
According to Newton's law of cooling, the rate of heat loss to the surroundings is proportional to the temperature difference between the body and the surroundings. dQ dt = k(T - T₀) Given that the heat capacity of the block is C = 80 J ^ C ⁻¹ and the room temperature is T₀ = 20^ C . Just after the heater is turned off at T = 30^ C , the rate of cooling is 0.2^ C s ⁻¹ . The rate of heat loss at this instant is: dQ dt = C (- dT dt ) = 80 0.2 = 16 W Substituting these values into Newton's law of cooling: 16 = k(30 -