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Concepts Of Physics MCQ Edition [Volume 2]
Exam
Concepts Of Physics MCQ Edition [Volume 2]
Subject
Physics
Chapter
Heat Transfer

Concepts Of Physics MCQ Edition [Volume 2] · Physics · Heat Transfer

A hot body placed in a surrounding of temperature θ_0 conforms to...

A hot body placed in a surrounding of temperature θ0\theta_0 conforms to Newton's law of cooling, dθdt=−k(θ−θ0)\dfrac{d\theta}{dt} = -k(\theta - \theta_0). At t=0t = 0, its temperature is θ1\theta_1. The mass of the body is mm and its specific heat capacity is ss. Determine the maximum heat that the body can lose.

Options

  1. Amsθ1ms\theta_1
  2. Bms(θ1+θ0)ms(\theta_1 + \theta_0)
  3. Cms(θ1−θ0)ms(\theta_1 - \theta_0)
  4. Dms(θ1−θ0)k\dfrac{ms(\theta_1 - \theta_0)}{k}

Correct answer

C. ms(θ1−θ0)ms(\theta_1 - \theta_0)

Step-by-step solution

The body cools down according to Newton's law of cooling and its temperature decreases until it reaches thermal equilibrium with the surroundings.

The minimum temperature the body can attain is the temperature of the surroundings, which is θ0\theta_0.

The initial temperature of the body is θ1\theta_1.

The maximum fall in temperature of the body is Δθ=θ1−θ0\Delta \theta = \theta_1 - \theta_0.

The maximum heat lost by the body is given by Q=msΔθQ = ms\Delta \theta.

Substituting the value of Δθ\Delta \theta, we get Q=ms(θ1−θ0)Q = ms(\theta_1 - \theta_0).
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