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JEE Main 20207 JanuaryMorning Shift
Exam
JEE Main
Year
2020
Date
7 January
Shift
Morning Shift
Subject
Chemistry
Chapter
Hydrocarbons

JEE Main 2020 · 7 January · Morning Shift · Chemistry · Hydrocarbons

Consider the following reactions: (a) (C H _ 3 ) _ 3 CCH(OH)C H _ 3...

Consider the following reactions:
(a)(CH3)3CCH(OH)CH3→conc.H2SO4\left(a\right) {\left(C{H}_{3}\right)}_{3}CCH\left(OH\right)C{H}_{3}\overset{conc . {H}_{2}S{O}_{4}}{\to}
\left(b\right) {\left(C{H}_{3}\right)}_{2}CHCH\left(Br\right)C{H}_{3}\overset{alc . KOH}{\to}<br/>(c)(CH3)2CHCH(Br)CH3→(CH3)3O⊖K⊕<br />\left(c\right) {\left(C{H}_{3}\right)}_{2}CHCH\left(Br\right)C{H}_{3}\overset{{\left(C{H}_{3}\right)}_{3}{O}^{⊖}{K}^{⊕}}{\to}
\left(d\right)$ Consider the following reactions: (a) (C H _ 3 ) _ 3 CCH(OH)C H _ 3 conc . H _ 2 S O _ 4 → (b) (C H _ 3 ) _ 2 CHCH(Br)C

Which of the reaction(s) will not produce Saytzeff product?

Options

  1. A(a),(c)\left(a\right), \left(c\right) and \left(d\right)
  2. B(d)\left(d\right) only
  3. C(c)\left(c\right) only
  4. D(b)\left(b\right) and (d)\left(d\right)

Correct answer

C. (c)\left(c\right) only

Step-by-step solution

Consider the following reactions: (a) (C H _ 3 ) _ 3 CCH(OH)C H _ 3 conc . H _ 2 S O _ 4 → (b) (C H _ 3 ) _ 2 CHCH(Br)C

We have to know that a Saytzeff product is basically an alkene compound which has undergone many substitution reactions to form the alkene product. From Saytzeff rule, a stable alkene is formed when removal of hydrogen from beta carbon has a low number of hydrogen atoms.

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