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JEE Main201910 Apr 2019Evening ShiftChemistryHydrocarbonsActual

The major product obtained in the given reaction is:

Correct answer

3

Step-by-step solution

We know that AlCl 3 is a lewis acid. It can give Friedel Crafts reactions. Here, we can see that AlCl 3 acts as a lewis acid and accepts the electron pair from the chlorine atom. This forms − AlCl 4 . Alongside this, a carbocation is also formed. Now, this carbocation is an electrophilic carbon. So, benzene rings can give electrophilic substitution reactions here. So, as a result, the double bond of benzene will attack on the carbocation and a C-C bond will be formed there. Then after losing a proton, the car

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