As depicted in the figure, a cylindrical tube of volume V having adiabatic walls contains an ideal gas. The internal energy of this ideal gas is given by 1.5 nRT . A fixed diathermic wall divides the tube into two equal parts. Initially, the pressure and temperature are p₁, T₁ on the left side and p₂, T₂ on the right side. The system is allowed sufficient time for the temperatures on both sides to become equal. Deter

Step-by-step solution

The problem states that the diathermic wall dividing the cylindrical tube is fixed. This means that the volume of both the left and right parts of the tube remains constant throughout the process. The work done by a gas is given by the integral of pressure with respect to volume: W = p , dV Since the volume of the left part is constant, the change in volume dV = 0 . Therefore, the work done by the gas in the left part is zero. The process is isochoric, and the heat exchanged only changes the internal energy of the