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JEE Main20198 Apr 2019Evening ShiftChemistryHydrocarbonsActual

Which one of the following alkenes when treated with H C l yields majorly an anti Markovnikov product?

Options

  1. AC H 3 O - C H = C H 2
  2. BC l - C H = C H 2
  3. CH 2 N - C H = C H 2
  4. DF 3 C - C H = C H 2

Correct answer

D. F 3 C - C H = C H 2

Step-by-step solution

Markovnikov’s product is formed when a stable carbocation is formed on the more substituted carbon. In C F 3 - C H = C H 2 , the carbocation formed will be destabilized by strong - I group of C F 3 . Hence, the Anti-Markovnikov’s product will be formed.

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