Which one of the following alkenes when treated with HCl yields...

Which one of the following alkenes when treated with

HCl

yields majorly an anti Markovnikov product? Which one of the following alkenes when treated with HCl yields majorly an anti Markovnikov product?

Which one of the following alkenes when treated with HCl yields majorly an anti Markovnikov product?

Options

A ${CH}_{3}O - CH = C{H}_{2}$
B $Cl - CH = C{H}_{2}$
C ${H}_{2}N - CH = C{H}_{2}$
D ${F}_{3}C - CH = C{H}_{2}$

Correct answer

D. ${F}_{3}C - CH = C{H}_{2}$

Step-by-step solution

Markovnikov’s product is formed when a stable carbocation is formed on the more substituted carbon.

In $C{F}_{3} - CH = C{H}_{2},$ the carbocation formed will be destabilized by strong $- I$ group of $C{F}_{3} .$ Hence, the Anti-Markovnikov’s product will be formed.

Which one of the following alkenes when treated with HCl yields majorly an anti Markovnikov product?

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