Two metal strips, each of length l , are clamped parallel to one another on a horizontal floor with a separation b between them. A wire of mass m lies perpendicularly across them, as shown in the figure. A vertically upward magnetic field of strength B is present in the space. The metal strips are smooth, whereas the coefficient of friction between the wire and the floor is . Once the switch S is closed at the instan

Step-by-step solution

While the wire is on the metal strips, it experiences a magnetic force due to the current flowing through it. The magnitude of this magnetic force is given by: F_m = i b B Since the metal strips are smooth, there is no frictional force acting on the wire during this part of the motion. The work done by the magnetic force as the wire moves along the entire length l of the strips is converted into its kinetic energy: W_m = F_m l = i b B l Let v be the velocity of the wire just as it leaves the metal strips. Its kinet