A current of 10 A is maintained in a long wire directed along the positive z -axis. Determine the magnetic field B at the point (1 m , 0, 0) .

Step-by-step solution

The magnetic field due to a long straight current-carrying wire is given by B = ₀ I 2 r Given I = 10 A and perpendicular distance r = 1 m Substituting the values: B = 4 10⁻⁷ 10 2 1 = 2 10⁻⁶ T = 2 T The direction of the magnetic field is given by the cross product d l r Since the current is along the positive z -axis ( d l k ) and the position vector is along the positive x -axis ( r = i ), the direction is along k i = j Thus, the magnetic field is 2 T along the positive y -axis