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Concepts Of Physics MCQ Edition [Volume 2]
Exam
Concepts Of Physics MCQ Edition [Volume 2]
Subject
Physics
Chapter
Magnetic Field due to a Current

Concepts Of Physics MCQ Edition [Volume 2] · Physics · Magnetic Field due to a Current

A long, straight wire of radius r carrying a uniformly distributed...

A long, straight wire of radius rr carrying a uniformly distributed current ii is positioned horizontally in a uniform magnetic field BB that is directed vertically upward. Determine the locations where the resultant magnetic field attains its maximum magnitude, and find this maximum magnitude.

Options

  1. ALooking along the direction of current, at the leftmost points on the wire's surface; B+μ0i2πrB + \dfrac{\mu_0 i}{2\pi r}
  2. BAt points lying on the central axis of the wire; B+μ0i2πrB + \dfrac{\mu_0 i}{2\pi r}
  3. CLooking along the direction of current, at the topmost points on the wire's surface; \sqrt{B^2 + \left(\dfrac{\mu_0 i}{2\pi r}\right)^2}
  4. DLooking along the direction of current, at the rightmost points on the wire's surface; B+μ0i2πrB + \dfrac{\mu_0 i}{2\pi r}

Correct answer

A. Looking along the direction of current, at the leftmost points on the wire's surface; B+μ0i2πrB + \dfrac{\mu_0 i}{2\pi r}

Step-by-step solution

Let the observer look along the direction of the current, meaning the current is flowing away from the observer into the plane.

According to the right-hand grip rule, the magnetic field lines produced by the straight wire form concentric clockwise circles around the wire.

The external uniform magnetic field is directed vertically upward.

To obtain the maximum resultant magnetic field, the magnetic field produced by the wire must be in the same direction as the external magnetic field (i.e., vertically upward).

Looking at the clockwise magnetic field lines, the tangent to the field lines points vertically upward at the leftmost points of the wire. At the rightmost points, the field points vertically downward.

The magnitude of the magnetic field due to the wire is maximum at its surface and is given by μ0i2πr\dfrac{\mu_0 i}{2\pi r}.

Thus, at the leftmost points on the wire's surface, both the external magnetic field and the wire's magnetic field are parallel and directed vertically upward. The maximum resultant magnetic field is the sum of their magnitudes:

Bnet=B+μ0i2πrB_{net} = B + \dfrac{\mu_0 i}{2\pi r}
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