Determine the net energy absorbed by an atom during a process in which it absorbs a photon of wavelength 500 nm and subsequently emits another photon of wavelength 700 nm .

Step-by-step solution

The net energy absorbed by the atom is the difference between the energy of the absorbed photon and the energy of the emitted photon. E = E_ absorbed - E_ emitted E = hc _ absorbed - hc _ emitted Substituting the given values, _ absorbed = 500 nm and _ emitted = 700 nm : E = hc ( 1 500 10⁻⁹ - 1 700 10⁻⁹ ) Using hc = 6.63 10⁻³⁴ 3 10^8 = 19.89 10⁻²⁶ J m : E = 19.89 10⁻²⁶ 10^9 ( 1 500 - 1 700 ) E = 19.89 10⁻¹⁷ ( 7 - 5 3500 ) E = 19.89 10⁻¹⁷ 2 3500 E = 39.78 10⁻¹⁷ 3500 1.136 10⁻¹⁹ J Rounding to two significant figures,