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Concepts Of Physics MCQ Edition [Volume 2]
Exam
Concepts Of Physics MCQ Edition [Volume 2]
Subject
Physics
Chapter
Photoelectric Effect and Wave–Particle Duality

Concepts Of Physics MCQ Edition [Volume 2] · Physics · Photoelectric Effect and Wave–Particle Duality

Compute the number of photons emitted per second by a 10 W sodium...

Compute the number of photons emitted per second by a 10 W10 \text{ W} sodium vapour lamp. Assume that 60%60\% of the consumed energy is converted into light. The wavelength of sodium light is 590 nm590 \text{ nm}.

Options

  1. A1.77×10181.77 \times 10^{18}
  2. B2.95×10192.95 \times 10^{19}
  3. C1.06×10191.06 \times 10^{19}
  4. D1.77×10191.77 \times 10^{19}

Correct answer

D. 1.77×10191.77 \times 10^{19}

Step-by-step solution

Power of the lamp, P=10 WP = 10 \text{ W}

Energy converted into light per second, Elight=60100×10=6 J/sE_{\text{light}} = \dfrac{60}{100} \times 10 = 6 \text{ J/s}

Wavelength of sodium light, λ=590 nm=590×10−9 m\lambda = 590 \text{ nm} = 590 \times 10^{-9} \text{ m}

Energy of one photon is given by E=hcλE = \dfrac{hc}{\lambda}

E=6.63×10−34×3×108590×10−9≈3.37×10−19 JE = \dfrac{6.63 \times 10^{-34} \times 3 \times 10^8}{590 \times 10^{-9}} \approx 3.37 \times 10^{-19} \text{ J}

Number of photons emitted per second, n=ElightEn = \dfrac{E_{\text{light}}}{E}

n=63.37×10−19≈1.77×1019n = \dfrac{6}{3.37 \times 10^{-19}} \approx 1.77 \times 10^{19}
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