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Concepts Of Physics MCQ Edition [Volume 2]
Exam
Concepts Of Physics MCQ Edition [Volume 2]
Subject
Physics
Chapter
Semiconductors and Semiconductor Devices

Concepts Of Physics MCQ Edition [Volume 2] · Physics · Semiconductors and Semiconductor Devices

An ideal p - n junction diode has a current-voltage characteristic...

An ideal pp-nn junction diode has a current-voltage characteristic described by i=i0 ⁣(eeV/kT−1)i = i_0 \! \left(e^{eV/kT} - 1\right), in which the drift current i0i_0 is 10$muA.Thetemperature10 \$mu\text{A}.The temperatureTistakenasis taken as300  K.Determineanexpressionforthediode′sdynamicresistanceasafunctionof\text{ K}.Determine an expression for the diode's dynamic resistance as a function ofVintheregionin the regionV > V_0(where(whereV_0isthevoltageatwhichis the voltage at whiche^{eV/kT} = 100,allowingtheterm, allowing the term1inthecurrentexpressiontobeneglected).in the current expression to be neglected).

Options

  1. Aei0kTeeV/kT\dfrac{e i_0}{kT} e^{eV/kT}
  2. BkTei0e−eV/kT\dfrac{kT}{e i_0} e^{-eV/kT}
  3. CkTei0eeV/kT\dfrac{kT}{e i_0} e^{eV/kT}
  4. Dei0kTe−eV/kT\dfrac{e i_0}{kT} e^{-eV/kT}

Correct answer

B. kTei0e−eV/kT\dfrac{kT}{e i_0} e^{-eV/kT}

Step-by-step solution

The current-voltage characteristic of the diode is given by i=i0(eeV/kT−1)i = i_0 (e^{eV/kT} - 1).

For V>V0V > V_0, the term eeV/kT≥100e^{eV/kT} \ge 100, so 11 can be neglected compared to eeV/kTe^{eV/kT}.

The expression for current becomes i≈i0eeV/kTi \approx i_0 e^{eV/kT}.

The dynamic resistance rdr_d of a diode is defined as rd=dVdir_d = \dfrac{dV}{di}.

Differentiating the current with respect to voltage VV, we get:

didV=ddV(i0eeV/kT)=ei0kTeeV/kT\dfrac{di}{dV} = \dfrac{d}{dV} (i_0 e^{eV/kT}) = \dfrac{e i_0}{kT} e^{eV/kT}

Therefore, the dynamic resistance is:

rd=1didV=kTei0e−eV/kTr_d = \dfrac{1}{\dfrac{di}{dV}} = \dfrac{kT}{e i_0} e^{-eV/kT}
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