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Concepts Of Physics MCQ Edition [Volume 2]PhysicsSemiconductors and Semiconductor Devices

Determine the current flowing through the circuit and the potential difference across the diode as depicted in the figure. The drift current of the diode is 20 A .

Options

  1. A250 mA , 4.9996 V
  2. B250 mA , 0.0004 V
  3. C20 A , 4.9996 V
  4. D20 A , 0.0004 V

Correct answer

C. 20 A , 4.9996 V

Step-by-step solution

From the given circuit diagram, the positive terminal of the battery is connected to the n-side (cathode) of the diode through the resistor, and the negative terminal is connected to the p-side (anode). This indicates that the diode is reverse-biased. In a reverse-biased p-n junction, the current flowing through the circuit is equal to the minority carrier drift current (reverse saturation current). Given the drift current is 20 A , the current in the circuit is: I = 20 A = 20 10⁻⁶ A The potential difference across

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