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Concepts Of Physics MCQ Edition [Volume 2]
Exam
Concepts Of Physics MCQ Edition [Volume 2]
Subject
Physics
Chapter
Specific Heat Capacities of Gases

Concepts Of Physics MCQ Edition [Volume 2] · Physics · Specific Heat Capacities of Gases

A given mass of a gas, with a specific heat ratio C_p / C_V = γ ,...

A given mass of a gas, with a specific heat ratio Cp/CV=γC_p / C_V = \gamma, has an initial pressure p0p_0 and an initial volume V0V_0. The gas is permitted to exchange heat with its surroundings. It is slowly compressed to a volume V0/2V_0 / 2 and subsequently suddenly compressed to V0/4V_0 / 4. Determine the final pressure of the gas.

Options

  1. A4p04 p_0
  2. B2γ+1p02^{\gamma + 1} p_0
  3. C22γp02^{2\gamma} p_0
  4. D2γp02^{\gamma} p_0

Correct answer

B. 2γ+1p02^{\gamma + 1} p_0

Step-by-step solution

The gas is slowly compressed while permitted to exchange heat with its surroundings, which indicates an isothermal process.

For an isothermal process, the equation of state is p1V1=p0V0p_1 V_1 = p_0 V_0.

Given V1=V02V_1 = \dfrac{V_0}{2}, the pressure after the first compression is:

p1=p0(V0V0/2)=2p0p_1 = p_0 \left( \dfrac{V_0}{V_0 / 2} \right) = 2 p_0

The gas is then suddenly compressed, which indicates an adiabatic process.

For an adiabatic process, the equation of state is p2V2γ=p1V1γp_2 V_2^{\gamma} = p_1 V_1^{\gamma}.

Given V2=V04V_2 = \dfrac{V_0}{4}, the final pressure is:

p2=p1(V1V2)γp_2 = p_1 \left( \dfrac{V_1}{V_2} \right)^{\gamma}

Substituting the values of p1p_1, V1V_1, and V2V_2:

p2=2p0(V0/2V0/4)γp_2 = 2 p_0 \left( \dfrac{V_0 / 2}{V_0 / 4} \right)^{\gamma}

p2=2p0(2)γ=2γ+1p0p_2 = 2 p_0 (2)^{\gamma} = 2^{\gamma + 1} p_0
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