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Concepts Of Physics MCQ Edition [Volume 2]
Exam
Concepts Of Physics MCQ Edition [Volume 2]
Subject
Physics
Chapter
Specific Heat Capacities of Gases

Concepts Of Physics MCQ Edition [Volume 2] · Physics · Specific Heat Capacities of Gases

An adiabatic cylindrical tube having a volume V_0 is separated into...

An adiabatic cylindrical tube having a volume V0V_0 is separated into two parts by a frictionless adiabatic separator. Initially, the separator is held in the middle. The left part is filled with an ideal gas at pressure p1p_1 and temperature T1T_1, while the right part contains another ideal gas at pressure p2p_2 and temperature T2T_2. The specific heat ratio, Cp/CV=γC_p / C_V = \gamma, is identical for both gases. The separator is subsequently slid slowly and released at a location where it can remain in equilibrium. Determine the heat given to the gas in the left part during this process.
An adiabatic cylindrical tube having a volume V_0 is separated into two parts by a frictionless adiabatic separator.

Options

  1. A(p1+p2)V0γ−1\dfrac{(p_1 + p_2) V_0}{\gamma - 1}
  2. B(p1−p2)V02(γ−1)\dfrac{(p_1 - p_2) V_0}{2 (\gamma - 1)}
  3. Cp1V02(γ−1)\dfrac{p_1 V_0}{2 (\gamma - 1)}
  4. D00

Correct answer

D. 00

Step-by-step solution

The cylindrical tube is given to be adiabatic, which means no heat can be exchanged between the gas and the surroundings through the outer walls.

The separator dividing the tube into two parts is also specified as adiabatic, meaning no heat can flow between the gas in the left part and the gas in the right part.

Since the gas in the left part is completely enclosed by adiabatic boundaries, it is perfectly thermally insulated.

By definition, in an adiabatic process, the heat exchange is zero. Even though work is done on or by the gas as the separator is slid slowly to a new equilibrium position, no heat is transferred.

Therefore, the heat given to the gas in the left part during this process is 00.
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