The mass of iron converted into Fe_3O_4 by the action of 18 g of steam is : (Given : Molar mass of H, O and Fe are 1 , 16 and 56 g mol ^ -1 respectively) Assume iron is present in excess :

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Quantrex Academy · Accepted Answer

Correct answer: D. 42 g

The balanced chemical equation for the reaction of iron with steam is:

3Fe + 4H_2O \rightarrow Fe_3O_4 + 4H_2

Molar mass of

H_2O = 2 \times 1 + 16 = 18 \text{ g mol}^{-1}

Number of moles of steam (

H_2O

) given =

\dfrac{18}{18} = 1 \text{ mol}

From the balanced equation,

4 \text{ moles}

of

H_2O

react with

3 \text{ moles}

of

Fe

.

Therefore,

1 \text{ mole}

of

H_2O

will react with

\dfrac{3}{4} \text{ moles}

of

Fe

.

Mass of iron reacted = Moles of

Fe \times

Molar mass of

Fe

Mass of iron =

\dfrac{3}{4} \times 56 = 3 \times 14 = 42 \text{ g}

Answer:

42

g

The mass of iron converted into Fe_3O_4 by the action of 18 g of...

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