Given below are two reactions, involved in the commercial production of dihydrogen ( H _ 2 ) . The two reactions are carried out at temperature “ T _ 1 ” and “ T _ 2 ”, respectively C(s) + H _ 2

Correct answer: D. T _ 1 > T _ 2 C (s) + H _ 2 O (g) 1270K( T _ 1 ) ⟶ CO(g) + H _ 2 (g) is known as coal gasification reaction. The mixture produced in this reaction is called water gas. CO(g) + H _ 2 O(g) 673K( T _ 2 ) Catalyst → CO _ 2 (g) + H _ 2 (g) is known as water gas shift reaction. Using water gas shift reaction we can increase the concentration of hydrogen gas. Hence, T _ 1 > T _ 2

JEE Main 202310 AprilMorning Shift

Exam: JEE Main
Year: 2023
Date: 10 April
Shift: Morning Shift
Subject: Chemistry
Chapter: Hydrogen

JEE Main 2023 · 10 April · Morning Shift · Chemistry · Hydrogen

Given below are two reactions, involved in the commercial...

Given below are two reactions, involved in the commercial production of dihydrogen $\left({H}_{2}\right)$ . The two reactions are carried out at temperature “ ${T}_{1}$ ” and “ ${T}_{2}$ ”, respectively

$C\left(s\right) + {H}_{2}O\left(g\right)\overset{{T}_{1}}{⟶}CO\left(g\right) + {H}_{2}\left(g\right)$

$CO\left(g\right) + {H}_{2}O\left(g\right)\dfrac{{T}_{2}}{Catalyst}{CO}_{2}\left(g\right) + {H}_{2}\left(g\right)$

The temperatures ${T}_{1}$ and ${T}_{2}$ are correctly related as

Options

A ${T}_{1} = {T}_{2}$
B ${T}_{1} < {T}_{2}$
C ${T}_{1} = 100K, {T}_{2} = 1270K$
D ${T}_{1} > {T}_{2}$

Correct answer

D. ${T}_{1} > {T}_{2}$

Step-by-step solution

$C$ \left(s\right) + {H}_{2}O $\left(g\right)\overset{1270K\left({T}_{1}\right)}{⟶}CO\left(g\right) + {H}_{2}\left(g\right)$ is known as coal gasification reaction. The mixture produced in this reaction is called water gas.
$CO\left(g\right) + {H}_{2}O\left(g\right)\dfrac{673K\left({T}_{2}\right)}{Catalyst} \to {CO}_{2}\left(g\right) + {H}_{2}\left(g\right)$ is known as water gas shift reaction. Using water gas shift reaction we can increase the concentration of hydrogen gas.
Hence, ${T}_{1} > {T}_{2}$

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