Two processes A and B on a system are illustrated in the figure....

According to the first law of thermodynamics, $\Delta Q = \Delta U + \Delta W$.

Since both processes $A$ and $B$ start from the same initial state and end at the same final state, the change in internal energy $\Delta U$ is the same for both processes.

The work done $\Delta W$ by the system is equal to the area under the $p-V$ curve. From the given graph, the area under the curve for process $A$ is greater than the area under the curve for process $B$. Thus, $\Delta W_A > \Delta W_B$.

Therefore, the heat given to the system during process $A$ is greater than that during process $B$, i.e., $\Delta Q_1 > \Delta Q_2$.