A circular loop with an area of 1 cm ^2 carrying a 10 A current is positioned in a 0.1 T magnetic field that is perpendicular to the plane of the loop. The torque exerted on the loop by the magnetic field is

Step-by-step solution

The magnetic moment of the circular loop is given by M = IA . Since the magnetic field is perpendicular to the plane of the loop, the angle between the area vector of the loop and the magnetic field is 0^ . The torque exerted on the loop is given by = MB . Substituting = 0^ , we get = MB 0^ = 0 .