A circular loop with an area of 1 cm^2 carrying a 10 A current is...

The magnetic moment of the circular loop is given by $M = IA$.

Since the magnetic field is perpendicular to the plane of the loop, the angle $\theta$ between the area vector of the loop and the magnetic field is $0^{{}^{{}^{\circ}}}$.

The torque exerted on the loop is given by $\tau = MB \sin \theta$.

Substituting $\theta = 0^{{}^{{}^{\circ}}}$, we get $\tau = MB \sin 0^{{}^{{}^{\circ}}} = 0$.