A beam comprising protons and electrons, travelling at the same speed, traverses a thin region containing a magnetic field perpendicular to the beam. The protons and the electrons

Step-by-step solution

The radius of the circular path of a charged particle in a perpendicular magnetic field is given by R = mv qB . For a thin region of magnetic field of width d , the angle of deviation is given by = d R = qBd mv . Since protons and electrons have different masses ( m_p m_e ) but the same magnitude of charge and same speed, their radii of curvature will be different ( R_p > R_e ). Therefore, their angles of deviation will be unequal ( _p Additionally, due to their opposite charges, they will experience magnetic force