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Concepts Of Physics MCQ Edition [Volume 2]
Exam
Concepts Of Physics MCQ Edition [Volume 2]
Subject
Physics
Chapter
Magnetic Field due to a Current

Concepts Of Physics MCQ Edition [Volume 2] · Physics · Magnetic Field due to a Current

A charged particle travels along a magnetic field line. The...

A charged particle travels along a magnetic field line. The magnetic force acting on the particle is

Options

  1. Aopposite to its velocity
  2. Bperpendicular to its velocity
  3. Czero
  4. Dalong its velocity

Correct answer

C. zero

Step-by-step solution

The magnetic force acting on a charged particle moving in a magnetic field is given by F⃗=q(v⃗×B⃗)\vec{F} = q(\vec{v} \times \vec{B}).

The magnitude of this force is F=qvBsin⁡θF = qvB\sin\theta, where θ\theta is the angle between the velocity vector v⃗\vec{v} and the magnetic field vector B⃗\vec{B}.

Since the particle is traveling along a magnetic field line, its velocity is either parallel (θ=0∘\theta = 0^{{}^{{}^{\circ}}}) or anti-parallel (θ=180∘\theta = 180^{{}^{{}^{\circ}}}) to the magnetic field.

In both cases, sin⁡θ=0\sin\theta = 0.

Therefore, the magnetic force acting on the particle is zero.
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