Identify the correct statement:

Gauss's law states that the total electric flux through any closed surface is equal to $\dfrac{1}{\epsilon_0}$ times the net charge enclosed by the surface.

The electric field $\vec{E}$ in the expression $\oint \vec{E} \cdot d\vec{A} = \dfrac{q_{enclosed}}{\epsilon_0}$ is the resultant electric field due to all charges present in space, both inside and outside the Gaussian surface.

However, the electric flux contributed by the charges situated outside the closed surface is zero, because any field line from an outside charge that enters the surface must also exit it. Therefore, the total flux of the electric field across the closed surface due to all charges is exactly equal to the flux due to only the charges enclosed by the surface.

Gauss's law is valid for any charge distribution (not just symmetrical ones) and in any medium (using the appropriate permittivity).