One mole of an ideal gas is kept in a rigid container of negligible heat capacity. If 3.0 cal of heat is supplied to the gas, its temperature rises by 1^ C . This gas could be

Step-by-step solution

For an isochoric process, the work done is zero. According to the first law of thermodynamics, the heat supplied is equal to the change in internal energy. Q = U = n C_v T Substituting the given values: 3.0 = 1 C_v 1 C_v = 3.0 cal mol ⁻¹ K ⁻¹ The molar heat capacity at constant volume is related to the degrees of freedom f by C_v = f 2 R . Using R 2 cal mol ⁻¹ K ⁻¹ : 3.0 = f 2 2 f = 3 A gas with 3 degrees of freedom is a monatomic gas. Among the given options, helium and argon are monatomic gases.