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JEE Main 202528 JanuaryEvening Shift
Exam
JEE Main
Year
2025
Date
28 January
Shift
Evening Shift
Subject
Chemistry
Chapter
Ionic Equilibrium

JEE Main 2025 · 28 January · Evening Shift · Chemistry · Ionic Equilibrium

Arrange the following in increasing order of solubility product :...

Arrange the following in increasing order of solubility product : Ca(OH)2,AgBr,PbS,HgS\mathrm{Ca}(\mathrm{OH})_2, \mathrm{AgBr}, \mathrm{PbS}, \mathrm{HgS}

Options

  1. AHgS<AgBr<PbS<Ca(OH)2\mathrm{HgS} \lt \mathrm{AgBr} \lt \mathrm{PbS} \lt \mathrm{Ca}(\mathrm{OH})_2
  2. BCa(OH)2<AgBr<HgS<PbS\mathrm{Ca}(\mathrm{OH})_2 \lt \mathrm{AgBr} \lt \mathrm{HgS} \lt \mathrm{PbS}
  3. CPbS<HgS<Ca(OH)2<AgBr\mathrm{PbS} \lt \mathrm{HgS} \lt \mathrm{Ca}(\mathrm{OH})_2 \lt \mathrm{AgBr}
  4. DHgS<PbS<AgBr<Ca(OH)2\mathrm{HgS} \lt \mathrm{PbS} \lt \mathrm{AgBr} \lt \mathrm{Ca}(\mathrm{OH})_2

Correct answer

D. HgS<PbS<AgBr<Ca(OH)2\mathrm{HgS} \lt \mathrm{PbS} \lt \mathrm{AgBr} \lt \mathrm{Ca}(\mathrm{OH})_2

Step-by-step solution

Based on the Ksp values and salt analysis cation identification, we can say that order of Ksp value is: HgS<PbS<AgBr<Ca(OH)2\mathrm{HgS} < \mathrm{PbS} < \mathrm{AgBr} < \mathrm{Ca}(\mathrm{OH})_2 K sp values HgS→4×10−53PbS→8×10−28AgBr→5×10−13Ca(OH)2→5.5×10−6\begin{aligned} & \mathrm{HgS} \rightarrow 4 \times 10^{-53} \\ & \mathrm{PbS} \rightarrow 8 \times 10^{-28} \\ & \mathrm{AgBr} \rightarrow 5 \times 10^{-13} \\ & \mathrm{Ca}(\mathrm{OH})_2 \rightarrow 5.5 \times 10^{-6} \end{aligned}
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