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JEE Main 202528 JanuaryMorning Shift
Exam
JEE Main
Year
2025
Date
28 January
Shift
Morning Shift
Subject
Chemistry
Chapter
Ionic Equilibrium

JEE Main 2025 · 28 January · Morning Shift · Chemistry · Ionic Equilibrium

A weak acid HA has degree of dissociation x . Which option gives...

A weak acid HA has degree of dissociation x . Which option gives the correct expression of ( pH pKa\mathrm{pK}_{\mathrm{a}} )?A weak acid HA has degree of dissociation x . Which option gives the correct expression of ( pH pK_ a )?

Options

  1. A0
  2. Blog⁡(1+2x)\log (1+2 \mathrm{x})
  3. Clog⁡(1−xx)\log \left(\frac{1-x}{x}\right)
  4. Dlog⁡(x1−x)\log \left(\frac{x}{1-x}\right)

Correct answer

D. log⁡(x1−x)\log \left(\frac{x}{1-x}\right)

Step-by-step solution

A weak acid HA has degree of dissociation x . Which option gives the correct expression of ( pH pK_ a )?
Ka=[H+](x)C(1−x)[H+]=Ka(1−x)xlog⁡H+=log⁡Ka+log⁡(1−xx)−log⁡H+=−log⁡Ka−log⁡1−xxpH=pKa−log⁡1−xxpH−pKa=log⁡x1−x\begin{aligned} & \mathrm{K}_{\mathrm{a}}=\frac{\left[\mathrm{H}^{+}\right](\mathrm{x})}{\mathrm{C}(1-\mathrm{x})} \\ & {\left[\mathrm{H}^{+}\right]=\mathrm{K}_{\mathrm{a}} \frac{(1-\mathrm{x})}{\mathrm{x}}} \\ & \log \mathrm{H}^{+}=\log \mathrm{K}_{\mathrm{a}}+\log \left(\frac{1-\mathrm{x}}{\mathrm{x}}\right) \\ & -\log \mathrm{H}^{+}=-\log \mathrm{K}_{\mathrm{a}}-\log \frac{1-\mathrm{x}}{\mathrm{x}} \\ & \mathrm{pH}=\mathrm{pK}_{\mathrm{a}}-\log \frac{1-\mathrm{x}}{\mathrm{x}} \\ & \mathrm{pH}-\mathrm{pK}_{\mathrm{a}}=\log \frac{\mathrm{x}}{1-\mathrm{x}}\end{aligned}
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