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At 298 K , the solubility of silver chloride in water is 1 . 434 × 10 - 3 g L - 1 . The value of - logK sp for silver chloride is (Given mass of Ag is 107 . 9 g mol - 1 , and mass of Cl is 35 . 5 g mol - 1 )

Correct answer

0

Step-by-step solution

Formula unit mass of Silver chloride = 108   +   35 . 5   gmol - 1   =   143 . 5   gmol - 1 Solubility ( s ) = 1 . 434 143 . 4 × 10 - 3 = 10 - 5 M ∴ K sp ( AgCl ) = [ Ag ] [ Cl ]   = ( s ) 2 ⇒ K sp ( AgCl ) = 10 - 10 ⇒ - log K sp = 10

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