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600 mL of 0 . 01 M HCl is mixed with 400 mL of 0 . 01 M H 2 SO 4 . The pH of the mixture is _____ × 10 - 2 . (Nearest integer) [Given log 2 = 0 . 30 , log 3 = 0 . 48 , log 5 = 0 . 69 , log 7 = 0 . 84 , log 11 = 1 . 04 ]

Correct answer

0

Step-by-step solution

The number of millimoles = Molarity   ×     Volume in mL HCl produce one and H 2 SO 4 produce two H + ions respectively. Total milimoles of H + = 600 × 0 . 01 + 400 × 0 . 01 × 2 = 14 Thus, moles of hydrogen ion: ⇒ H + = 14 1000 = 14 × 10 - 3 ⇒ pH   =   - log [ H + ] = - log [ 14   ×   10 - 3 ] ⇒ pH = 3 - log 14 = 1 . 86 = 186 × 10 - 2

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