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JEE Main 202324 JanuaryEvening Shift
Exam
JEE Main
Year
2023
Date
24 January
Shift
Evening Shift
Subject
Chemistry
Chapter
Ionic Equilibrium

JEE Main 2023 · 24 January · Evening Shift · Chemistry · Ionic Equilibrium

If the pKa of lactic acid is 5 , then the pH of 0 . 005M calcium...

If the pKapKa of lactic acid is 55, then the pHpH of 0.005M0 . 005M calcium lactate solution at 25°C25 ° C is __________ ×10–1\times {10}^{– 1} (Nearest integer)

Correct answer

0

Step-by-step solution

Concentration of calcium lactate = 0.005M0 . 005M

concentration of lactate ion = =(2×0.005)M= ( 2 \times 0 . 005 ) M

Calcium lactate is a salt of weak acid + strong base

∴∴ Salt hydrolysis will take place for a basic salt:

⇒pH=7+12pKa+12logC=7+12×5+12log⁡(0.01)=85×10−1⇒ pH = 7 + \dfrac{1}{2}pKa + \dfrac{1}{2}logC = 7 + \dfrac{1}{2} \times 5 + \dfrac{1}{2}\log ( 0 . 01 ) = 85 \times {10}^{- 1}

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