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JEE Main202228 Jun 2022Evening ShiftChemistryIonic EquilibriumActual

A student needs to prepare a buffer solution of propanoic acid and its sodium salt with pH 4 . The ratio of CH 3 CH 2 COO - CH 3 CH 2 COOH required to make buffer is Given : K a CH 3 CH 2 COOH = 1 . 3 × 10 - 5

Options

  1. A0 . 03
  2. B0 . 13
  3. C0 . 23
  4. D0 . 33

Correct answer

B. 0 . 13

Step-by-step solution

Henderson's equation for calculating p H of acidic buffer solutions is given as pH = pK a + log Salt Acid pH = pK a + log CH 3 COO - CH 3 COOH 4 = 5 - log ( 1 . 3 ) + log CH 3 COO - CH 3 COOH log 1 . 3 × 10 - 1 = log CH 3 COO - CH 3 COOH CH 3 COO - CH 3 COOH = 0 . 13

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