p ^ H value of 0 . 001MNaOH solution is

Concentration of $NaOH$ given is $0 . 001M$

$\left[{OH}^{-}\right] = 0 . 001 = 1 \times {10}^{- 3}$

${p}^{OH} = - \log \left[{OH}^{-}\right]</p><p>$= - \log \left(1 \times {10}^{- 3}\right)=

$= 3{p}^{H} = 14 - {p}^{OH}$

$= 14 - 3 = 11$

Hence, the ${p}^{H} of the given solution of$NaOH$is 11.</p>$