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JEE Main 202118 MarchMorning Shift
Exam
JEE Main
Year
2021
Date
18 March
Shift
Morning Shift
Subject
Chemistry
Chapter
Ionic Equilibrium

JEE Main 2021 · 18 March · Morning Shift · Chemistry · Ionic Equilibrium

In order to prepare a buffer solution of pH5 . 74 , sodium acetate...

In order to prepare a buffer solution of pH5.74pH5 . 74, sodium acetate is added to acetic acid. If the concentration of acetic acid in the buffer is 1.0M,1 . 0M, the concentration of sodium acetate in the buffer is ______M.M . (Round off to the Nearest Integer). \left[Given: pKa\left(\text{acetic acid}\right) = 4 . 74\right]

Correct answer

0

Step-by-step solution

pH=pKa+log[CB][WA]pH = pKa + log\dfrac{[ CB ]}{[ WA ]}
5.74=4.74+log[CB]15 . 74 = 4 . 74 + log\dfrac{[ CB ]}{1}
⇒[CB]=10M⇒ [ CB ] = 10M

\left[CB\right] =Conjugatebase.</p><p>[WA]=Conjugate base.</p><p>\left[WA\right] =Weak acid

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