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JEE Main202118 Mar 2021Morning ShiftChemistryIonic EquilibriumActual

In order to prepare a buffer solution of pH 5 . 74 , sodium acetate is added to acetic acid. If the concentration of acetic acid in the buffer is 1 . 0 M , the concentration of sodium acetate in the buffer is ______ M . (Round off to the Nearest Integer). Given : pKa acetic acid = 4 . 74

Correct answer

0

Step-by-step solution

pH = pKa + log [ CB ] [ WA ] 5 . 74 = 4 . 74 + log [ CB ] 1 ⇒ [ CB ] = 10 M CB   = Conjugate base. WA   = Weak acid

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